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CGP EDU Academic Team
Published on: September 11, 2026
Two identical capacitors are joined in parallel, charged to a potential V and then separated and then connected in series i.e. the positive plate of one is connected to negative of the other
Text Solution
Verified by ExpertsThe correct answer is:
D
$Q_1 = CV$ and $Q_{2} = CV$
Applying charge conservation $cV_{1} + cV_{2} = Q_{1} + Q_{2}$
$cV_1 + cV_2 = 2cV$ ⇒ ⇒ $V_1 + V_2 \equiv 2V$
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