The unit of Stefan's constant \(\delta\) is

Physics Units, Dimensions and Measurement Units Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: September 12, 2026

W m^{-2} K^{-1}

\(W \, m^{2} \, K^{-4}\)

W m^{-2} K^{-4}

Text Solution

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The correct answer is:

Stefan's law is \(E = \sigma T^{4}\) ⇒ ⇒ \(\sigma = \frac{E}{T^4}\)

where, \bar{E} = \(\frac{\text{Energy}}{\text{Area} \times \text{Time}}\) \(= \frac{\text{Watt}}{m^{2}}\)

\(\sigma = \frac{\text{Watt} \cdot m^{-2}}{K^{4}} = \text{Watt} \cdot m^{-2} K^{-4}\)

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