Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two infinitely long parallel wires having linear charge densities $\lambda_1$ and $\lambda_2$ respectively are placed at a distance of R meters. The force per unit length on either wire will be $\left( K = \frac{1}{4 \pi \varepsilon_0} \right)$
Text Solution
Verified by ExpertsThe correct answer is:
B
Force on l length of the wire 2 is
$F_2 = QE_1 = (\lambda_2 l) \frac{2k \lambda_1}{R}$
⇒ ⇒ $\frac{F_2}{l} = \frac{2k \lambda_1 \lambda_2}{R}$
Also $\frac{F_1}{l} = \frac{F_2}{l} = \frac{F}{l} = \frac{2k \lambda_1 \lambda_2}{R}$
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