A positively charged ball hangs from a silk thread. We put a positive test charge $\alpha_0$ at a point and measure $F / q_0$ , then it can be predicted that the electric field strength $\Gamma$
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Because of the presence of positive test charge q 0 in front of positively charged ball, charge on the ball will be redistributed, less charge on the front half surface and more charge on the back half surface. As a result of this net force F between ball and point charge will decrease i.e. actual electric field will be greater than $F/q_0\cdot$
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