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CGP EDU Academic Team
Published on: September 12, 2026
A non-conducting ring of radius 0.5 m carries a total charge of $1.11 \times 10^{-10} \, \mathrm{C}$ distributed non-uniformly on its circumference producing an electric field 
everywhere in space. The value of the line integral $\int_{l=\infty}^{l=0} \vec{E} . d\vec{l} (l=0)$ being center of the ring) in volt is
Text Solution
Verified by ExpertsThe correct answer is:
A
$\int_{-\infty}^{0} - \vec{E} \cdot d\vec{l}$ = potential at center of non-conducting ring
$=\frac{1}{4 \pi \varepsilon_0} \times \frac{q}{r} = \frac{9 \times 10^9 \times 1.11 \times 10^{-10}}{0.5} = 2 \text{ volt}$
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