Charge q is uniformly distributed over a thin half ring of radius R. The electric field at the centre of the ring is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
From figure dl = R d θ θ ;
Charge on dl = λ λ R d θ θ 
Electric field at centre due to dl is 
.
We need to consider only the component 
as the component dE sin θ θ will cancel out because of the field at C due to the symmetrical element dl ′ ′ .
Total field at center 
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