Two equal charges are separated by a distance d. A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force when
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
Suppose third charge is similar to Q and it is q
So net force on it
F net = 2F cos θ θ
Where 
and 
∴ ∴ 
For F net to be maximum 
i.e. 
or 
i.e. 
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