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CGP EDU Academic Team
Published on: September 12, 2026
A piece of cloud having area $25 \times 10^{6} \, m^{2}$ and electric potential of $10^{5}$ volts. If the height of cloud is $0.75\,km$ , then energy of electric field between earth and cloud will be
Text Solution
Verified by ExpertsThe correct answer is:
D
Energy $= \frac{1}{2} \varepsilon_0 E^2 \times (A \times d)$ $= \frac{1}{2} \varepsilon_0 \left(\frac{V^2}{d^2}\right) A d$
$= \frac{1}{2} \times \frac{8.85 \times 10^{-12} \times (10^{5})^{2} \times 25 \times 10^{6}}{0.75 \times 10^{3}} = 1475 \, J$
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