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CGP EDU Academic Team
Published on: September 12, 2026
The electromotive force of a primary cell is 2 volts. When it is short-circuited it gives a current of 4 amperes. Its internal resistance in ohms is
Text Solution
Verified by ExpertsThe correct answer is:
A
$E' = V + ir$
After short-circuiting, $\mathbf{V} = 0;$ ⇒ ⇒ $r = \frac{E}{i} = \frac{2}{4} = 0.5 \Omega$
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