The resistance of a galvanometer is 50 ohms and the current required to give full scale deflection is $100 \mu A$ . In order to convert it into an ammeter, reading upto 10 A , it is necessary to put a resistance of
Text Solution
Verified by ExpertsB
The resistance of the galvanometer $G = 50 \Omega$ . The current required for a full scale deflection $I_{g} = 100 \mu A$ .
Maximum range of current to be measured I = 10 A Now to convert this galvanometer into an ammeter, we need to put a shunt S in parallel as,
$S = \frac{I_g G}{I - I_g} = \frac{100 \times 10^{-6}}{10 - 100 \times 10^{-6}} \times 50$
$= 5 \times 10^{-4} \Omega$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems