In a metre bridge experiment null point is obtained at 20 cm from one end of the wire when resistance X is balanced against another resistance Y. If X < Y, then where will be the new position of the null point from the same end, if one decides to balance a resistance of 4X against Y
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We have from meter bridge experiment, $\frac{R_1}{R_2} = \frac{\ell_1}{\ell_2}$, where $\ell_2 = (100 - \ell_1) \text{ cm}$ In the first case, $\frac{X}{Y} = \frac{20}{80}$ In the second case $\frac{4X}{Y} = \frac{\ell}{100 - \ell}$ $\ell = 50 \text{ cm}$.
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