Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two positive point charges of $12 \mu C$ and $8 \mu C$ are 10cm apart. The work done in bringing them 4 cm closer is
Text Solution
Verified by ExpertsThe correct answer is:
C
$W = U_f - U_i = 9 \times 10^9 \times Q_1 Q_2 \left[\frac{1}{r_2} - \frac{1}{r_1}\right]$
⇒ ⇒ $W = 9 \times 10^{9} \times 12 \times 10^{-6} \times 8 \times 10^{-6} \left[ \frac{1}{4 \times 10^{-2}} - \frac{1}{10 \times 10^{-2}} \right]$
= 12.96 J ≈ ≈ 13 J
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