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CGP EDU Academic Team
Published on: September 12, 2026
The displacement of a charge $Q$ in the electric field $\mathbf{E} = e_1 \hat{\mathbf{i}} + e_2 \hat{\mathbf{j}} + e_3 \hat{\mathbf{k}}$ is $\hat{r} = a\hat{i} + b\hat{j}$ . The work done is
Text Solution
Verified by ExpertsThe correct answer is:
A
By using $W = Q \overrightarrow{(E . \Delta r)}$
⇒ ⇒ $W = Q[(e_1 \hat{i} + e_2 \hat{j} + e_3 \hat{k}) \cdot (a \hat{i} + b \hat{j})] = Q(e_1 a + e_2 b)$
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