Two small spherical balls each carrying a charge $Q = 10 \mu C$ ( 10 micro-coulomb) are suspended by two insulating threads of equal lengths 1m each, from a point fixed in the ceiling. It is found that in equilibrium threads are separated by an angle $60^\circ$ between them, as shown in the figure. What is the tension in the threads (Given: $\frac{1}{(4 \pi \varepsilon_0)} = 9 \times 10^9 \mathrm{Nm/C^2}$ )
Text Solution
Verified by ExpertsB
In the following figure, in equilibrium F e = T sin 30 o , r = 1m
⇒ ⇒ $9 \times 10^{9} \cdot \frac{Q^{2}}{r^{2}}$ = $T \times \frac{1}{2}$
⇒ ⇒ $9 \times 10^{9} \cdot \frac{\left(10 \times 10^{-6}\right)^{2}}{1^{2}} = T \times \frac{1}{2}$ 
T = 1.8 N
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems