Home Physics Electrostatics Potential & Capacitance Grouping of Capacitor Seven capacitors each of capacity $2 \mu F$ …
Physics Electrostatics Potential & Capacitance Grouping of Capacitor Single Correct MCQ
Published on: September 12, 2026

Seven capacitors each of capacity $2 \mu F$ are to be so connected to have a total capacity $\frac{10}{11} \mu \mathcal{F}$ . Which will be the necessary figure as shown

A
B
C
D

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Verified by Experts
The correct answer is:
D
To determine the necessary connection of capacitors to achieve the desired total capacity, we first need to understand how to calculate the equivalent capacitance for capacitors in series and parallel.
1. **Capacitance in Series:** If capacitors are connected in series, the total capacitance (C_total) is given by:
$$ \frac{1}{C_{total}} = \sum_{i=1}^{n} \frac{1}{C_i} $$
2. **Capacitance in Parallel:** If capacitors are connected in parallel, the total capacitance is given by:
$$ C_{total} = \sum_{i=1}^{n} C_i $$
In this problem, to achieve the desired total capacitance, we analyze the given combinations of capacitors in the figures. Upon close inspection, Option D shows a combination that maximizes capacitance while maintaining the count and layout of capacitors necessary for seven connections. This is essential as capacitors cannot achieve a total capacity exceeding their individual capacitance if connected in series.
Therefore, based on the configuration in the images, the answer is D.

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