Consider a parallel plate capacitor of $10 \mu \mathrm{F}$ (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant 4 , as shown in the figure. The capacity of the capacitor changes to
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$C_1 = \frac{\varepsilon_0 \left(\frac{A}{4}\right)}{d}, C_2 = \frac{K \varepsilon_0 \left(\frac{A}{2}\right)}{d}, C_3 = \frac{\varepsilon_0 \left(\frac{A}{4}\right)}{d}$
$C_{eq} = C_1 + C_2 + C_3 = \left(\frac{K+1}{2}\right) \frac{\varepsilon_0 A}{d}$ $= \left(\frac{4+1}{2}\right) \times 10 = 25 \mu F$
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