Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Electric potential at any point is $V = -5x + 3y + \sqrt{1 5z}$ , then the magnitude of the electric field is
Text Solution
Verified by ExpertsThe correct answer is:
D
$E_x = -\frac{dV}{dx} = -(-5) = 5;$
$E_{y} = -\frac{dV}{dy} = -3$
and $E_z = -\frac{dV}{dz} = -\sqrt{15}$
$E_{net} = \sqrt{E_x^2 + E_y^2 + E_z^2} = \sqrt{(5)^2 + (-3)^2 + \left(-\sqrt{15}\right)^2} = 7$
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