A block of mass 2 kg rests on a rough inclined plane making an angle of 30 0 with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is:
A
9.8 N
B
0.7 × 9.8 
N
N
C
9.8 × 7 N
D
0.8 × 9.8 N
Text Solution
Verified by ExpertsThe correct answer is:
A
since; gkW µ> tan θ
the block will not slide therefore f = mg sin θ
= 2 × 9.8 × 
= 9.8 N.
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