In an induction coil with resistance, the induced emf will be maximum when

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CGP EDU Academic Team · Accepted Answer

The correct answer is C. When the switch is put on in an induction coil, it creates a change in current flow, inducing an electromotive force (emf) due to Faraday's law of electromagnetic induction. The induced emf is given by:  $$ \text{emf} = -L \frac{dI}{dt} $$  where L is the inductance and $\frac{dI}{dt}$ is the rate of change of current.    **Option A**: If the switch is put on due to high resistance, the initial current may be low, resulting in a lower rate of change of current and therefore a lower induced emf.  **Option B**: If the switch is put off due to high resistance, there will be no change in current (I = 0), and thus, no induced emf.  **Option C**: If the switch is put on due to low resistance, the rate of change of current will be high initially, leading to a maximum induced emf at the moment the switch is closed.  **Option D**: If the switch is put off due to low resistance, the current is again steady (I = constant), leading to no emf.   Therefore, the induced emf will be maximum when the switch is put on due to low resistance.

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