Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Unit of magnetic permeability is
Text Solution
Verified by ExpertsThe correct answer is:
D
Step 1: Understand the concept of magnetic permeability. Magnetic permeability ($\mu$) is a measure of how easily a magnetic field can penetrate a material. It is defined as the ratio of magnetic flux density ($B$) to magnetic field strength ($H$). The relationship can be expressed as:
$$\mu = \frac{B}{H}$$
Step 2: Determine the units of $B$ and $H$. The unit of magnetic flux density ($B$) is the Tesla (T), which can be expressed in terms of basic SI units as:
$$1 ext{ T} = 1 \frac{N}{A imes m} = 1 \frac{kg}{A \times s^2}$$
The unit of magnetic field strength ($H$) is Ampere per meter (A/m).
Step 3: Rewrite the unit of permeability using the units of $B$ and $H$:
$$\mu = \frac{B}{H} = \frac{T}{A/m} = \frac{1 \frac{kg}{A \times s^2}}{\frac{A}{m}}$$
Simplifying this gives:
$$\mu = \frac{kg \times m}{A^2 \times s^2}$$
Step 4: Analyze the options provided:
- Option A: Amp/meter
- Option B: Amp/m²
- Option C: Henry
- Option D: Henry/meter (Henry is defined as $\frac{V \cdot s}{A}$, or equivalently, $\frac{kg}{A^2 \cdot s^2}$, which relates to the unit of magnetic permeability.)
Conclusion: Given that Henry is a unit of inductance and has the dimension similar to magnetic permeability, the correct choice which aligns with the SI unit for magnetic permeability ($\frac{H}{m}$) is Option D: Henry/meter.
$$\mu = \frac{B}{H}$$
Step 2: Determine the units of $B$ and $H$. The unit of magnetic flux density ($B$) is the Tesla (T), which can be expressed in terms of basic SI units as:
$$1 ext{ T} = 1 \frac{N}{A imes m} = 1 \frac{kg}{A \times s^2}$$
The unit of magnetic field strength ($H$) is Ampere per meter (A/m).
Step 3: Rewrite the unit of permeability using the units of $B$ and $H$:
$$\mu = \frac{B}{H} = \frac{T}{A/m} = \frac{1 \frac{kg}{A \times s^2}}{\frac{A}{m}}$$
Simplifying this gives:
$$\mu = \frac{kg \times m}{A^2 \times s^2}$$
Step 4: Analyze the options provided:
- Option A: Amp/meter
- Option B: Amp/m²
- Option C: Henry
- Option D: Henry/meter (Henry is defined as $\frac{V \cdot s}{A}$, or equivalently, $\frac{kg}{A^2 \cdot s^2}$, which relates to the unit of magnetic permeability.)
Conclusion: Given that Henry is a unit of inductance and has the dimension similar to magnetic permeability, the correct choice which aligns with the SI unit for magnetic permeability ($\frac{H}{m}$) is Option D: Henry/meter.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A length of wire carries a steady current . It is bent first to form a circular plane coil of one…
The strength of the magnetic field at a point r near a long straight current carrying wire is B. Th…
Field at the center of a circular coil of radius r, through which a current I flows is
In the figure, shown the magnetic induction at the center of there arc due to the current in portio…
In the above question, the magnetic induction at O due to the whole length of the conductor is
Two straight horizontal parallel wires are carrying the same current in the same direction, d is th…