A person wears glasses of power – 2.0 D . The defect of the eye and the far point of the person without the glasses will be
Text Solution
Verified by ExpertsThe correct answer is:
A
The defect is myopia (nearsightness)
As we know for myopic person f = – (defected far point)
⇒ ⇒ Defected far point = – f = – 
= 50 cm
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