A bullet of mass M is fired with a velocity of 50 ms -1 at an angle θ θ with the horizontal. At the highest point of trajectory, it collides with a bob of mass 3M suspended vertically by a massless string of length 10/3m and gets embedded into it. After the collision the string moves through an angle 120 0 =, what is the angle of throw θ θ .
Text Solution
Verified by ExpertsThe correct answer is:
C
Velocity at highest point = u cos θ θ
Then Mu cos θ θ = (M + 3M) v
or v = 
and 4 Mgh = 
Using the given values, we get
or cos 2 θ θ = 
or cos θ θ = 
or θ θ = cos -1 
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