Two identical blocks are kept on rough inclined plane (µ = 0.5). The blocks are connected with light string. If mg < F < 2mg, then -

Text Solution
Verified by ExpertsThe correct answer is:
B
Figure shows forces acting along the string

∴ f +
= F – mg
⇒ f = F – 
∴ If F <
⇒ f: – ve ⇒ Friction force on block ‘B’ is in upward direction.
F >
⇒ f: + ve ⇒ friction force on block ‘B’ is in downward direction.
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