A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. If g = 10 m s –2 , then the magnitude of the force acting upwards at an angle of 60º from the horizontal that will just start the block moving is -
Text Solution
Verified by ExpertsB
Force acting on the block
Weight of block downward direction
Normal reaction R upward direction
Vertical component of applied force 
And horizontal forces
Horizontal component of force 
Friction force between block and table 
Values are given in question
Now equate vertical forces
Put given value
Friction force given as 
… .(1)
Now equate all the horizontal forces
Put value from equation (1)
Solving this
Rearranging this
So the value of applied force
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems