Home Physics Newton's Laws of Motion Motion of Connected Bodies Blocks A and B in the figure are connected b…
Physics Newton's Laws of Motion Motion of Connected Bodies MCQ (Single Correct)

Blocks A and B in the figure are connected by a bar of negligible weight. If A = B = 170 kg &µ A = 0.2 and µ B = 0.4, where µ A and µ B are the coefficients of limiting friction between blocks and plane, calculate the force on the bar: (g = 10 m/s 2 )

A
150 N
B
75 N
C
200 N
D
250 N

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Text Solution

Verified by Experts
The correct answer is:
A

For → mg sin θ – T – μ Α mg cos θ = ma.…(1)

For → T + mg sin θ – μ Β mg cos θ = ma .... (2)

⇒ mg sin θ –T– μ A mg cos θ = T + mg sin θ – μ B mg cos θ

⇒ T = ( μ B – μ A )

= (0.4–0.2) = 150N

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