A block is kept on a smooth inclined plane of angle of inclination 30 0 that moves with a constant acceleration so that the block does not slide relative to the inclined plane. Let F 1 be the contact force between the block and the plane. Now the inclined plane stops and let F 2 be the contact force between the two in this case. Then F 1 /F 2 is -
Text Solution
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When block does not slide w.r.t. incline plane,
F 1 = normal reaction = mg cos θ + ma sin θ
a = g tan θ
∴ F 1 = mg cos θ + m (g tan θ ) sin θ
= mg sec θ = mg sec 30 0 = 
When incline plane is stationary,
F 2 = mg cos θ = mg cos 30º = 
∴ 
= 
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