In order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration 5g/4 relative to the rope. The tension in the rope is: (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
C
If 'a' is the acceleration of body w.r.t. ground then acceleration of man w.r.t. ground = 
Thus, for body,
T – 100 g = 100 a .... (i)
for man, T – 60 g = 
T = 135 g – 60 a .... (ii)
By solving eq. (i) and (ii)
T = 1218 N
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