A uniform chain of mass m hangs from a light pulley, with unequal lengths hanging from the two sides of the pulley. The force exerted by the moving chain on the pulley is
Text Solution
Verified by ExpertsThe correct answer is:
C
Let the masses of the section of the chain on the two sides be M and ( 
), with 
. Let a be the acceleration of the chain, and T be the tension in the chain at the points where it meets the pulley. Then, 
and 
.
Eliminating a and rearranging, 
. The force exerted by the chain on the pulley is 2 T . This will be less than mg as 
.
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