Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The potential energy for a conservative system is given by U = ax 2 – bx
Column-I | Column-II |
(i) The net force acting on the system | [A] b/2a |
(ii) The equilibrium Position | [B] b – 2ax |
(iii) The potential energy at the Equilibrium position | [C] – b2/4a |
(iv) The equilibrium | [D] stable |
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Identify the expression for potential energy: U = ax^2 - bx.
Step 2: Calculate the force acting on the system, which is the negative gradient of potential energy: F = -\frac{dU}{dx} = -\frac{d}{dx}(ax^2 - bx) = -2ax + b.
Step 3: Set the force equal to zero for equilibrium: -2ax + b = 0, which gives us x = \frac{b}{2a}.
Thus, the net force acting on the system is correctly identified as [A] \frac{b}{2a}.
Step 4: To find the equilibrium position, equate the first derivative of potential energy to zero. The expression derived indicates that at this value of x, the force is balanced.
Therefore, A.
Step 2: Calculate the force acting on the system, which is the negative gradient of potential energy: F = -\frac{dU}{dx} = -\frac{d}{dx}(ax^2 - bx) = -2ax + b.
Step 3: Set the force equal to zero for equilibrium: -2ax + b = 0, which gives us x = \frac{b}{2a}.
Thus, the net force acting on the system is correctly identified as [A] \frac{b}{2a}.
Step 4: To find the equilibrium position, equate the first derivative of potential energy to zero. The expression derived indicates that at this value of x, the force is balanced.
Therefore, A.
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