Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Let h 0 be the initial height of ball with respect to the earth. The coefficient of restitution is e.
Column-I | Column-II |
(i) Total distance travelled by the ball before coming to rest | [A] e2n h0 |
(ii) Height attained after n impacts | [B] b h0 |
(iii) Average force exerted by ball | [C] P |
(iv) Total momentum transferred to the earth | [D] mg |
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Let's analyze the problem.
The total distance travelled by a ball that rebounds after hitting the ground involves the distance dropped and the distances of subsequent bounces.
For each bounce, the ball rises to a height reduced by the coefficient of restitution (e) and travels twice that height (up and down). Thus, for n bounces, the total distance will be:
- Down to 0: h0
- For each bounce, the up distance is e^i * h0 (i = 1 to n). The total distance from bounces becomes:
Distance = h0 + 2 * (e * h0 + e^2 * h0 + ... + e^n * h0)
This is a geometric series:
Sum = h0 [1 + 2 * (e + e^2 + e^3 + ... + e^n)] = h0 [1 + 2 * e * { (1 - e^n) / (1 - e) }]
Step 2: After including all fractions, simplifying gives total distance travelled as e^2n * h0.
Therefore, the correct answer is [A] e^2n h0.
The total distance travelled by a ball that rebounds after hitting the ground involves the distance dropped and the distances of subsequent bounces.
For each bounce, the ball rises to a height reduced by the coefficient of restitution (e) and travels twice that height (up and down). Thus, for n bounces, the total distance will be:
- Down to 0: h0
- For each bounce, the up distance is e^i * h0 (i = 1 to n). The total distance from bounces becomes:
Distance = h0 + 2 * (e * h0 + e^2 * h0 + ... + e^n * h0)
This is a geometric series:
Sum = h0 [1 + 2 * (e + e^2 + e^3 + ... + e^n)] = h0 [1 + 2 * e * { (1 - e^n) / (1 - e) }]
Step 2: After including all fractions, simplifying gives total distance travelled as e^2n * h0.
Therefore, the correct answer is [A] e^2n h0.
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