Figure shows two blocks. A rough surface are identified as shown in figure. Blocks and man are initially at rest. The man started running with non-zero acceleration on surface 'A' and jumps on surface 'C' and stays there stationary w.r.t. other block. Then –
Column I | Column II |
(i) Direction of contact force on ' A ' when man is on ' A ' | [D] |
(ii) Direction of contact force on surface B when man is on A | [B] |
(iii) Direction of contact force on surface ' C ' when man | [C] |
(iv) Direction of contact force on surface ' D ' when man reaches at ' C ' | [D] |
Text Solution
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Step 2: When the man jumps from A to C, he will exert a force on B, which will push against A, and there will be a reactionary force on A.
Step 3: Regarding surface B, as the man runs on A, the direction of contact force on B (due to block A) will be opposite to the man's acceleration.
Step 4: On surface C, when the man stays stationary w.r.t. block C, there is a reaction force on C due to the man's weight acting downwards. The direction of the force exerted by the man on C will be downwards as he transitions from running to standing on C.
Therefore, the correct match for Column I (ii) is the direction of the contact force on C, which is [C].
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