A man of mass M is standing on a platform of mass m 1 and holding a string passing over a system of ideal pulley. Another mass m 2 is hanging as shown
(m 2 = 20kg, m 1 = 10 kg, g = 10m/s 2 ):
Column I | Column II |
(i) Weight of man for equilibrium | [A] 100 N |
(ii) Force exerted by man, on string to accelerate upwards | [B] 150 N |
(iii) Force exerted by man, on string to accelerate downward | [C] 500 N |
(iv) Normal reaction of platform on man is equilibrium | [D] 600 N |
[E] 700 N |
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)-[C], (ii)-[C], [D], [E], (iii)-[A], [B], (iv)-[A]
Sol
T = 200 N, 2T = 400 N
100 + Mg = 600
Mg = 500 N
N = 500 – 400 = 100
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