Two blocks P and Q of masses 0.3 kg and 0.4 kg respectively are stuck to each other by some weak glue as shown in the figure. They hang together at the end of a spring with a spring constant k = 200 N/m. The block Q suddenly falls free due to failure of glue, then find maximum kinetic energy of the block P during subsequent motion in mJ.

Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(40)
Sol. A = 
= 2 cm motion starts from lower extreme
KE max =
mꞷ 2 A 2 =
× 0.3 ×
A 2 =
× 0.3 ×
× 
= 0.04 J
= 40 mJ
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A vessel containing water is given a constant acceleration a towards the right, along a straight ho…
A ship of mass initially at rest is pulled by a force of through a distance of 3 m. Assume that t…
The mass of a body measured by a physical balance in a lift at rest is found to be m. If the lift i…
Three weights W, 2W and 3W are connected to identical springs suspended from a rigid horizontal rod…
When forces are acting on a particle of mass m such that and are mutually perpendicular, then th…
The spring balance A reads 2 kg with a block m suspended from it. A balance B reads 5 kg when a bea…