Home Physics Newton's Laws of Motion Motion of Connected Bodies A wedge of mass M = 2 m 0 rests on a smooth …
Physics Newton's Laws of Motion Motion of Connected Bodies MCQ (Single Correct)

A wedge of mass M = 2 m 0 rests on a smooth horizontal plane. A small block of mass m 0 rests over it at left end A as shown in figure. A sharp impulse is applied on the block, due to which it starts moving to the right with velocity v 0 = 6 m/s. At highest point of its trajectory, the block collides with a particle of same mass m 0 moving vertically downwards with velocity v = 2 m/s and gets stuck with it. If the combined mass lands at the end point A of the body of mass M, calculate length 𝓁 in cm. Neglect friction, take g = 10 m/s 2 .

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(0040)

Sol.

At highest point combined mass velocity is

H = = 1m

1.2 = 1.T + g T 2 T = 0.4 sec

u rel = 1 m/s

= u rel T = 0.4 m

= 40 cm

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