Figure give the x-t plots of a particle executing one-dimensional simple harmonic motion

Match the Column I with Column II
Column I Time | Column II Signs of position (x), velocity (v) and acceleration (a) | ||
(A) | At t = -1.2 s | (p) | x < 0, v < 0, a > 0 |
(B) | At t = -0.3 s | (q) | x > 0, v > 0, a < 0 |
(C) | At t = 0.3 s | (r) | x > 0, v < 0, a < 0 |
(D) | At t = 1.2 s | (s) | x < 0, v > 0, a > 0 |
Text Solution
Verified by ExpertsA
In SHM, accelerations , a = 
Where
(i.e., angular frequency) is constant.

At 
The slope of x –t is positive, hence v is positive.
Since
hence a is positive
At t = - 1.2 s, x < 0 , v > 0, a > 0
A – s
At 
The slope of x-t is negative hence v is negative.
Since a
hence a < 0
B –r
At 
The slope of x – t is negative hence v is negative.
Since
hence a > 0
C – p
At 
The slope of x – t is positive, hence v is positive,
Since a
hence a < 0
At t
x > 0, v > 0, a < 0
D- q
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