A particle is moving in a plane with velocity given by
= u 0
+ (a ω ω cos ω ω t)
, where
and
are unit vectors along x and y axis, respectively. If the particle is at origin at t = 0, the distance from origin at time 3 π π /2 ω ω is
Text Solution
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Given, u = u 0
+ (a ω ω cos ω ω t) 
Thus velocity along y axis, U y = a cos ω ω t and velocity along x axis, vx = u 0 .
Displacement at time t in horizontal direction,
x = 
and y = 
Eliminating t, y = a sin ( ω ω x/u 0 )
At time 3 π π /2 ω ω , x = u 0 (3 π π /2 ω ω )
and y = a sin 3 π π /2 = -a
Thus distance of particle from origin
S = 
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