A train moves from one station to another in 2 hrs time, its speed during the motion is shown in graph
below. The maximum acceleration during the journey and distance covered during the time interval from 0.75 hour to 1.00 hour are
Text Solution
Verified by ExpertsThe correct answer is:
B
Maximum acceleration during journey = slope of CD
= 
= 160 km hr -2
Distance covered in the asked interval
= Area of rectangle KCGH + Area of Δ Δ CDG.
= (0.25 × 20) + 1/2(40 × 0.25) = 5 + 5 = 10 km
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