A body when projected vertically up, covers a total distance D during its time of flight. If there were no gravity, the distance covered by it during the same time is equal to
Text Solution
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The displacement of the body during the time t as it reaches the point of projection
⇒ ⇒ S = 0 ⇒ ⇒ v 0 t − − 
gt 2 = 0
⇒ ⇒ 
During the same time t, the body moves in absence of gravity through a distance
D ′ ′ = v.t, because in absence of gravity g = 0
⇒ ⇒ D ′ ′ = 
…(1)
In presence of gravity the total distance covered is
= D = 2H = 
…(2)
(1) ÷ ÷ (2) ⇒ ⇒ D ′ ′ = 2D, Hence is correct.
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