Two cars are moving with same velocity of 30 kmh -1 maintaining a distance of 5 km between them. Speed of third car moving in the opposite direction and meeting the two cars at an interval of 240s is
Text Solution
Verified by ExpertsThe correct answer is:
A
Time interval,
t = distance between car/relative velocity
= d/v III + 30
where v III is velocity of 3 rd car and velocity of I or II is 30 kmh -1 or
240/3600 = 5/v III + 30 or
v III = (15 × 5 - 30)
= 45 kmh -1
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