Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Add vectors A, B and C each having magnitude of 100 unit and inclined to the x-axis at angles 45º, 135º and 315º respectively.
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: Resolve each vector into its components.
For vector A:
Magnitude = 100 units, Angle = 45º
Ax = 100 * cos(45º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
Ay = 100 * sin(45º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
For vector B:
Magnitude = 100 units, Angle = 135º
Bx = 100 * cos(135º) = 100 * -\frac{\sqrt{2}}{2} = -50\sqrt{2}
By = 100 * sin(135º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
For vector C:
Magnitude = 100 units, Angle = 315º
Cx = 100 * cos(315º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
Cy = 100 * sin(315º) = 100 * -\frac{\sqrt{2}}{2} = -50\sqrt{2}
Step 2: Sum the components of the vectors:
Total X-component = Ax + Bx + Cx = 50\sqrt{2} - 50\sqrt{2} + 50\sqrt{2} = 50\sqrt{2}
Total Y-component = Ay + By + Cy = 50\sqrt{2} + 50\sqrt{2} - 50\sqrt{2} = 50\sqrt{2}
Step 3: In resultant vector R, we have:
Rx = 50\sqrt{2}
Ry = 50\sqrt{2}
R = \sqrt{(R_x^2 + R_y^2)} = \sqrt{((50\sqrt{2})^2 + (50\sqrt{2})^2)} = \sqrt{(5000 + 5000)} = \sqrt{10000} = 100 units
Step 4: The angle θ with respect to the x-axis is given by:
θ = tan-1(Ry/Rx) = tan-1(1) = 45º.
Therefore, the resultant vector R has a magnitude of 100 units and is inclined at an angle of 45º to the x-axis.
For vector A:
Magnitude = 100 units, Angle = 45º
Ax = 100 * cos(45º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
Ay = 100 * sin(45º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
For vector B:
Magnitude = 100 units, Angle = 135º
Bx = 100 * cos(135º) = 100 * -\frac{\sqrt{2}}{2} = -50\sqrt{2}
By = 100 * sin(135º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
For vector C:
Magnitude = 100 units, Angle = 315º
Cx = 100 * cos(315º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
Cy = 100 * sin(315º) = 100 * -\frac{\sqrt{2}}{2} = -50\sqrt{2}
Step 2: Sum the components of the vectors:
Total X-component = Ax + Bx + Cx = 50\sqrt{2} - 50\sqrt{2} + 50\sqrt{2} = 50\sqrt{2}
Total Y-component = Ay + By + Cy = 50\sqrt{2} + 50\sqrt{2} - 50\sqrt{2} = 50\sqrt{2}
Step 3: In resultant vector R, we have:
Rx = 50\sqrt{2}
Ry = 50\sqrt{2}
R = \sqrt{(R_x^2 + R_y^2)} = \sqrt{((50\sqrt{2})^2 + (50\sqrt{2})^2)} = \sqrt{(5000 + 5000)} = \sqrt{10000} = 100 units
Step 4: The angle θ with respect to the x-axis is given by:
θ = tan-1(Ry/Rx) = tan-1(1) = 45º.
Therefore, the resultant vector R has a magnitude of 100 units and is inclined at an angle of 45º to the x-axis.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
There are two force vectors, one of 5 N and other of 12 N at what angle the two vectors be added to…
If \vec{A} = 4\hat{i} - 3\hat{j} and \vec{B} = 6\hat{i} + 8\hat{j} then magnitude and direction of …
A truck travelling due north at 20 m/s turns west and travels at the same speed. The change in its …
If the sum of two unit vectors is a unit vector, then magnitude of difference is
\vec{A} = 2\hat{i} + \hat{j}, \vec{B} = 3\hat{j} - \hat{k} and \vec{c} = 6\hat{i} - 2\hat{k} , Valu…
An object of m kg with speed of v m/s strikes a wall at an angle q and rebounds at the same speed…