Home Physics Vectors Addition and Subtraction of Vectors Add vectors A, B and C each having magnitude…
Physics Vectors Addition and Subtraction of Vectors Subjective Type
Published on: September 12, 2026

Add vectors A, B and C each having magnitude of 100 unit and inclined to the x-axis at angles 45º, 135º and 315º respectively.

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The correct answer is:
A
Step 1: Resolve each vector into its components.
For vector A:
Magnitude = 100 units, Angle = 45º
Ax = 100 * cos(45º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
Ay = 100 * sin(45º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}

For vector B:
Magnitude = 100 units, Angle = 135º
Bx = 100 * cos(135º) = 100 * -\frac{\sqrt{2}}{2} = -50\sqrt{2}
By = 100 * sin(135º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}

For vector C:
Magnitude = 100 units, Angle = 315º
Cx = 100 * cos(315º) = 100 * \frac{\sqrt{2}}{2} = 50\sqrt{2}
Cy = 100 * sin(315º) = 100 * -\frac{\sqrt{2}}{2} = -50\sqrt{2}

Step 2: Sum the components of the vectors:
Total X-component = Ax + Bx + Cx = 50\sqrt{2} - 50\sqrt{2} + 50\sqrt{2} = 50\sqrt{2}

Total Y-component = Ay + By + Cy = 50\sqrt{2} + 50\sqrt{2} - 50\sqrt{2} = 50\sqrt{2}

Step 3: In resultant vector R, we have:
Rx = 50\sqrt{2}
Ry = 50\sqrt{2}

R = \sqrt{(R_x^2 + R_y^2)} = \sqrt{((50\sqrt{2})^2 + (50\sqrt{2})^2)} = \sqrt{(5000 + 5000)} = \sqrt{10000} = 100 units

Step 4: The angle θ with respect to the x-axis is given by:
θ = tan-1(Ry/Rx) = tan-1(1) = 45º.

Therefore, the resultant vector R has a magnitude of 100 units and is inclined at an angle of 45º to the x-axis.

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