The distance between two moving points at any time is ‘a’ and their relative velocity is ‘v’, u and υ being components of ‘v’ respectively along and perpendicular to the direction of ‘a’. Show that their distance when they are nearest to one another is 
and the time elapses before they arrive at their nearest distance is 
.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
After time t s = (a – 4t) 2 + v 2 t 2 for S = min. ds/dt = 0 find t and substitute in S to get S min.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
There are two force vectors, one of 5 N and other of 12 N at what angle the two vectors be added to…
If and then magnitude and direction of will be
A truck travelling due north at 20 m/s turns west and travels at the same speed. The change in its …
If the sum of two unit vectors is a unit vector, then magnitude of difference is
and , Value of would be
An object of m kg with speed of v m/s strikes a wall at an angle q and rebounds at the same speed…