Trajectory of particle in a projectile motion is given as: y = x – . Here, x and y are in meters. For this projectile motion match the following with g = 10 m/s 2 . Column IColumn II(i) Angle of projection[A] 20m(ii) Angle of velocity with Horizontal after 4s[B] 80 m(iii) Maximum height [C] 45º(iv) Horizontal range[D] tan–1(1/2)

Trajectory of particle in a projectile motion is given as: …

Physics Motion in a Plane Mix MCQ (Single Correct)

Trajectory of particle in a projectile motion is given as:

y = x – . Here, x and y are in meters. For this projectile motion match the following with g = 10 m/s 2 .

Column I	Column II
(i) Angle of projection	[A] 20m
(ii) Angle of velocity with Horizontal after 4s	[B] 80 m
(iii) Maximum height	[C] 45º
(iv) Horizontal range	[D] tan–1(1/2)

Text Solution

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The correct answer is:

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Ans.

(i) [C]

(ii) [C]

(iii) [A]

(iv) [B]

Sol. Comparing with the standard equation of projectile, we get, and
Time period of this projectile is 4 s. Hence, after 4 s velocity vector will again make with horizontal.