In Fig., the blocks are of equal mass. The pulley is fixed. In the positive shown, A moves down with a speed u and 
the speed of B.
A
B will never lose contact with the ground.
B
The downward acceleration of A is equal in magnitude to the horizontal acceleration of B.
C
D
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, d): Let the lengths of the sections of the string be BP = l 1 and PA = l 2 in the position shown. Let B move through a small horizontal distance x to B' and A move down through a distance y to A'. Length of the string.
= BP + PA = B'P + PA'.
l 1 + l 2 = (l 1 – x cos θ θ ) + l 2 + y
or 
= 
cos θ θ
or v A = v B cos θ θ = u
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A body of mass hangs at one end of a string of length l , the other end of which is fixed. It is g…
The tension in the string revolving in a vertical circle with a mass m at the end which is at the l…
A stone of mass m is tied to a string and is moved in a vertical circle of radius r making n revolu…
A tube of length is filled completely with an incompressible liquid of mass and closed at both th…
The kinetic energy of a particle moving along a circle of radius depends on the distance covered …
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/sec . A…