Two towers AB and CD are situated a distance ‘d’ apart as shown in figure. AB is 20 m high and CD is 30 m high from the ground. An object of mass m is thrown from the top of AB horizontally with the velocity of 10 ms–1 towards CD. Simultaneously another object of mass 2 m is thrown from the top of CD at an angle of 60º to the horizontal towards AB with the same magnitude of initial velocity as that of the first object. The two objects move in the same vertical plane, collide in mid-air and stick to each other.
Text Solution
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Let 
be the time taken for collision. For mass m thrown horizontally from A for horizontal motion,
For vertical motion, 
From mass 2m thrown from C, for horizontal motion
For vertical motion : 
)
From (ii) and (vi), 
Applying the conservation of linear momentum (during collision of the masses at
M) in the horizontal direction, we have
Since the horizontal momentum comes out to be zero, the combination of masses will drop vertically downwards
Method 2 : Acceleration of A and C both is 
downward.
Therefore, the relative acceleration between them is zero, i.,e., the relative motion between them will be a straight line.
Now assuming A to be at rest, the condition of collision will be that 
relative velocity of 
.t. A should be along CA
or 
.
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