A sphere of mass 0.1 kg is attached to a cord of 1m length. Starting from the height of its point of suspension this sphere hits a block of same mass at rest on a frictionless table, If the impact is elastic, then the kinetic energy of the block after the collision is
Text Solution
Verified by ExpertsA
: As two blocks are of same mass and the collision is perfectly elastic therefore their velocities gets interchanged i.e. the block A comes into rest and complete kinetic energy transferred to block B.
Now kinetic energy of block B after collision = Kinetic energy of block A before collision
= Potential energy of block A at the original height
= mgh = 0.1 × × 10 × × 1 = 1 J.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems