Three particles A, B and C of equal mass are moving with the same velocity v along the medians of an equilateral triangle. These particles collide at the centre G of triangle. After collision A becomes stationary, B retraces its path with velocity v then the magnitude and direction of velocity of C will be
Text Solution
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From the figure (I) it is clear that before collision initial
momentum of the system = 0
After the collision, A becomes stationary, B retraces its path with velocity v. Let C moves with velocity V making an angle θ θ from the horizontal. As the initial momentum of the system is zero, therefore horizontal and vertical momentum after the collision should also be equal to zero.
From figure (II) Horizontal momentum
…...(i)
Vertical momentum 
…...(ii)
By solving (i) and (ii) we get 
and V = v i.e. the C will move with velocity v in the direction of B.
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