A 500 g ball is released from a height of 4 m. Each time it makes contact with the ground it loses 25% of its energy. Find the KE it possess after 3 rd hit:
Text Solution
Verified by ExpertsThe correct answer is:
C
After first hit K. E 1 = e 2 K.E
3/4 K.E = e 2 K.E
e 2 = 3/4
K.E. after third hit = e 2(3) . K.E = 27/64 (mgh)
= 
= 27 
= 8.44 J
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