A bomb of mass 9 kg explodes into the fragments of masses 3 kg and 6 kg. The velocity of mass 3 kg is 16 m/sec. The energy of explosion is equal to:
Text Solution
Verified by ExpertsThe correct answer is:
B
Conservation of momentum just before and after the impact yields
Pi = P f
⇒ ⇒ 0 = 
⇒ ⇒ m 1 v 1 = m 2 v 2 = p (say)
⇒ ⇒ Energy of explosion = Δ Δ KE system
= 
= 
Putting P = m 1 v 1 , where m 1 = 3 kg, M 2 = 6 kg, v = 16 m/sec.
We obtain, E = 
⇒ ⇒ E = 576 J.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A neutron travelling with a velocity v and K.E. E collides perfectly elastically head on with the n…
A ball bounces to 80% of its original height. What fraction of its mechanical energy is lost in eac…
The negative of the work done by the conservative internal forces on a system equals to the change …
A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal …
The bob of a pendulum is released from a horizontal position If the length of pendulum is 2 m, what…
A ball of mass m is dropped from a cliff of height H. The ratio of its kinetic energy to the potent…