Two identical disks are stacked coaxially at the two ends of cylinder as shown in figure. The system is made to roll down an inclined plane. Velocity of the system (disks + cylinder) when it touches the ground is v 0 . Angle of inclination is θ = 450 and coefficient of friction between ground and the disks is µ= 
. If coefficient of restitution between ground and disk is e = 1, then -
v 0
Text Solution
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(b, c)
x–axis | y–axis |
ux = v0 cos θ vx =? = mvx – mux vx = v0 cos θ + 2v0 sin θ × µ = v0 (sin θ + cos θ) \ vx = | uy = v0 sin θ vy = – v0 sin θ (e = 1) Impulse in y–direction vy = |
v = 
= 
v 0
At the time of collision, there will be backward slipping.
Work done by friction is positive.
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