A

Step 1: For a closed-end organ pipe, the fundamental frequency (first harmonic) is determined by the formula:
$$ f = \frac{v}{4L} $$
where

• $f$ is the frequency of the fundamental tone,
• $v$ is the speed of sound in the medium,
• $L$ is the length of the organ pipe.

Step 2: Since the problem states that the organ pipe has a length of \( \lambda \), we can substitute \(L = \lambda\) into the formula:
$$ f = \frac{v}{4\lambda} $$
Step 3: The problem mentions that only odd harmonics are present.
Therefore, the fundamental tone of a closed-end organ pipe produces frequencies based on this equation, confirming that it indeed only emits odd harmonics.
Hence, the answer is A.